Physics, asked by krubha3529, 11 months ago

The height of jar is 15 cm . It contains a liquid of mass 5 kg and density 900 kg m ³ . The pressure exerted by the liquid on the base of the jar is

Answers

Answered by muscardinus
2

Pressure exerted by the liquid on the base of the jar, P = 1338.79 Pa

Explanation:

Given that,

Height of the jar, h = 15 cm = 0.15 m

Mass, m = 5 kg

Density of the liquid, d=900\ kg/m^3

The density of any material is given by :

d=\dfrac{m}{V}

V=\dfrac{m}{d}  

V=\dfrac{5\ kg}{900\ kg/m^3}  

V = 0.0055

If A is the area of jar,

V=A\times h=0.0055

A=0.0366\ m^2

Let P is the pressure exerted by the liquid on the base of the jar. It is given by :

P=\dfrac{F}{A}

P=\dfrac{mg}{A}

P=\dfrac{5\times 9.8}{0.0366}

P = 1338.79 Pa

So, the pressure exerted by the liquid on the base of the jar is 1338.79 Pa. Hence, this is the required solution.

Learn more :

Topic : Pressure

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