The height of one object on the ground from the top of a tree was 60 degrees. 1.5 meters below the top of the tree
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tan 45° AC
BC
80
1=;
BC
BC = 80cm
DE
tan 30 BC +CE
80
1
V3
80+x
80 +x == 80V3
x= 80v3 - 80
x = 80(V3-1)m
The bird travelled 8(V3 - 1)m
Distance
Speed of bird =
Time
40(V3 1)
=
2
= 40(V3 -1)m/s
.. Speed = 40(V3- 1)m/s,
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