Question

The height of one object on the ground from the top of a tree was 60 degrees. 1.5 meters below the top of the tree​

Answer 1

tan 45° AC

BC

80

1=;

BC

BC = 80cm

DE

tan 30 BC +CE

80

1

V3

80+x

80 +x == 80V3

x= 80v3 - 80

x = 80(V3-1)m

The bird travelled 8(V3 - 1)m

Distance

Speed of bird =

Time

40(V3 1)

=

2

= 40(V3 -1)m/s

.. Speed = 40(V3- 1)m/s,