Question

③ The height of parallelogram is one third of it
area of parallelogram is 192 CM² find leight
have if​

Answer 1

Correct Question :-

The height of the parallelogram is one third of it area of parallelogram is 192cm² find its height and base

Given :-

• Area of parallelogram is 192cm²

• The height of the parallelogram is 1/3rd of its area

To Find :-

• Height and the base of the given parallelogram

Solution :-

Let the base and height of the parallelogram be

x and 1/3x

Now,

We know that,

Area of parallelogram = Base * Height

Subsitute the required values,

192 = x * 1/3x

192 = x²/3

192 * 3 = x²

x² = 576

x = √576

x = √ 24 * 24

x = 24

Hence, Base of the parallelogram is 24cm

Height of the parallelogram

= 1/3 * 24 = 8cm$.$

Answer 2

$olution:

Let the height of the parallelogram be h cm and base be b cm.

$According \: to \: the \: question \: h= \frac{1}{3} b$

$Area \: of \: parallelogram= base \times height$

$b \times h = 192$

$= > b \times \frac{1}{3} b = 192$

$= > {b}^{2} = 192 \times 3$

$= > {b}^{2} = 576$

$= > b = \sqrt{576 \: \: }$

$= > \: b = 24 \: cm$

$But \: given \: h = \frac{1}{3} b$

$= > \: h = \frac{1}{3 } \times 24$

$= > \: h = 8 \: cm$

$Height \: of \: the \: parallelogram \: = h = 8 \: cm$

$Base \: = b = 24 \: cm$