The height of parallelogram is one third of its base. if the area of parallelogram is 108 cm square. then find its base and height
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Here is your answer...✌
Let the height and base of parallelogram be h and b respectively.
Given that,
Height of parallelogram is one third of its base.
i.e., h = (1/3)×b ⇒b = 3h
And,
Area of parallelogram = 108 cm²
b × h = 108
3h × h = 108
h² = 108/3
h² = 36
⇒h = 6 cm
Therefore , b = 3×6 = 18
⇒b = 18 cm
Hence,
Height and Base of given parallelogram is 6cm and 18 cm respectively.
Here is your answer...✌
Let the height and base of parallelogram be h and b respectively.
Given that,
Height of parallelogram is one third of its base.
i.e., h = (1/3)×b ⇒b = 3h
And,
Area of parallelogram = 108 cm²
b × h = 108
3h × h = 108
h² = 108/3
h² = 36
⇒h = 6 cm
Therefore , b = 3×6 = 18
⇒b = 18 cm
Hence,
Height and Base of given parallelogram is 6cm and 18 cm respectively.
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