The height of right triangle is 7cm less than its base .if the hypotenuse is 13cm form the quadratic equation to find the base of the triangle
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24
Given that The altitude of a right triangle is 7 cm less than its base:-
Altitude is = x - 7 cm
Given that hypotenuse = 13cm.
Applying Pythagoras theorem,
base2+ altitude2 = hypotenuse2
plug the values we get
x2+ ( x – 7)2 = 132
x2+ x2+ 49 – 14 x = 169
2 x2 – 14 x + 48 – 169 = 0
2 x2 – 14 x – 120 = 0
Divide by 2 to both side to simplify it
x2 – 7 x – 60 = 0
x2 – 12 x + 5 x – 60 = 0
x ( x – 12) + 5 ( x – 12) = 0
( x – 12)( x + 5) = 0
x – 12 = 0 or x + 5 = 0
x = 12 or x = –5
length can not negative so that x can not equal to – 5
base x = 12cm
altitude = 12 – 7 = 5cm
Altitude is = x - 7 cm
Given that hypotenuse = 13cm.
Applying Pythagoras theorem,
base2+ altitude2 = hypotenuse2
plug the values we get
x2+ ( x – 7)2 = 132
x2+ x2+ 49 – 14 x = 169
2 x2 – 14 x + 48 – 169 = 0
2 x2 – 14 x – 120 = 0
Divide by 2 to both side to simplify it
x2 – 7 x – 60 = 0
x2 – 12 x + 5 x – 60 = 0
x ( x – 12) + 5 ( x – 12) = 0
( x – 12)( x + 5) = 0
x – 12 = 0 or x + 5 = 0
x = 12 or x = –5
length can not negative so that x can not equal to – 5
base x = 12cm
altitude = 12 – 7 = 5cm
Answered by
6
Answer:
Let base = x cm and height = (x - 7) cm
Hypotenuse = 13 cm
By Pythagoras theorem,
x2 + (x - 7)2 = 132 x=12 or x=-5
x2 + 49 + x2 - 14x = 169
2x2 - 14x - 120 = 0
x2 - 12x + 5x - 60 = 0
x(x - 12) + 5 (x - 12) = 0 (x - 12) (x + 5) = 0
X - 12 = 0 or x + 5 = 0
The other two sides are 12 cm and 5 cm.
Hope it was help full
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