Question

The height of the equilateral triangle whose base is 10 cm is (A) 52 cm (B) 573 cm (C) 6 13 cm (D) 62 cm​

Answer 1

Step-by-step explanation:

Also, since the height is √32s , we can say the height is 5√3 m .

Answer 2

Answer:

$given \\ The \: height \: of \: the \\ equilateral \: triangle \: whose \: base \: is \: 10 cm$

$to \: find \: the \: height \: of \: the \: triangle$

$height \: of \: triangle \: is \: also \\ called \: as \: altitude \: of \: triangle$

$base = 10cm$

$altitude \: of \: equilateral \: triangle = \frac{1}{2} \times \sqrt{3} \times b$

$(b \: is \: base)$

$on \: substituting \: the \: values \: we \: get$

$= \frac{1}{2} \times \sqrt{3} \times 10cm$

$by \: cancelling \: we \: get$

$= 5 \times \sqrt{3}$

$= 5 \times 1.73205081$

$= 8.66025405$

therefore height of the equilateral triangle is 8.66025405cm Or 5√3cm

Step-by-step explanation:

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