Question

the height of the triangle 7 cm and area of triangle is 49 cm^2 find the measure of the base​

Answer 1

Answer:

the formula to find the area of the triangle is 1/2 × base × height....now put the values and calculate yourself...

all the best

Answer 2

Step-by-step explanation:

Question :-

• The height of the triangle is 7 cm and area of triangle is 49 cm². Find the measure of the base.

To Find :-

• Base of the triangle.

Solution :-

Given :

• Height = 7 cm
• Area = 49 cm²

By using the formula,

${\sf{\longrightarrow Area\ of\ triangle\ =\ \dfrac{1}{2} \times b \times h}}$

Where,

• b = base
• h = height

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ triangle\ =\ \dfrac{1}{2} \times b \times h}}$

${\sf{\longrightarrow 49\ =\ \dfrac{1}{2} \times b \times 7}}$

${\sf{\longrightarrow \dfrac{49}{7}\ =\ b}}$

${\sf{\longrightarrow 7\ =\ b}}$

${\sf{\longrightarrow b\ =\ 7\ cm}}$

$\therefore$ Hence, base of the triangle is 7 cm.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$