Question

The height of tower and distance of a point from the foot of tower is equal,. Then find the angle of elevation from that point to the top of tower

Answer 1

Let the height of tower be x

∴ The distance of the foot from the point is also x

Let the angle of elevation be ∅

∴ tan∅ = Perpendicular/Base

⇒ tan∅ = x/x

⇒ tan∅ = 1

∴ ∅= 45°

Since tan45°=1

Answer 2

let AB= height of tower =x
and BC=distance =x

and angle=a

then tan a=perpendicular/base=AB/BC
=x/x=1. (tan45°=1)

tana=tan45°
a=45°

hence angle of elevation is 45°

hope it will help you