Question

the height of tower is 15m what is the length of its shadow on the ground when angle of elevation of the sun is 60°

Answer 1

The length of the shadow will be 4.33m

Answer 2

$\huge \bf \blue{Hey \: there !! }$



▶ Given :-

→ Height of the tower AB = 15 cm .

→ Angle of elevation of sun to the ground = 60° .



▶ To find :-

→ Length of shadow on the ground BC = ? .



$\huge \pink{ \mid{ \underline{ \overline{ \sf Solution :- }} \mid}}$



In right ∆ ABC,


$\sf \therefore \tan60 \degree = \frac{AB}{BC} . \\ \\ \sf \implies \sqrt{3} = \frac{15}{BC} . \\ \\ \sf \implies BC = \frac{15}{ \sqrt{3} } \\ \\ \sf \implies BC = \frac{15}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } . \\ \\ \sf \implies BC = \frac{15 \sqrt{3} }{ { (\sqrt{3} )}^{2} } . \\ \\ \sf \boxed{ \orange{ \sf \therefore BC = \frac{15 \sqrt{3} }{3}cm .}} \\ \\ \huge \sf or \\ \\ \boxed{ \green{ \sf \therefore BC =8.66cm. }}$



✔✔ Hence, it is solved ✅✅.



THANKS



#BeBrainly.