Question

the height of tower is √3 times the more than its shadow then angle of elevation of sun is ???
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Answer 1

Answer:

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Answer 2

Answer:

Let height of tower (AB) be h metres

Then length of its shadow will be BC=

3

hmetres

Let angle of elevation be θ

Now, In △ABC

tanθ=

B

P

=

BC

AB

tanθ=

3

h

h

=

3

1

⇒θ=30

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