the height of tower is √3 times the more than its shadow then angle of elevation of sun is ???
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Let height of tower (AB) be h metres
Then length of its shadow will be BC=
3
hmetres
Let angle of elevation be θ
Now, In △ABC
tanθ=
B
P
=
BC
AB
tanθ=
3
h
h
=
3
1
⇒θ=30
o
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