Question

the height of triangle ABC and triangle DBC are 4 cm and 6 cm respectively find A(triangle ABC) upon A(triangle DBC)​

Answer 1

Answer:

GIVEN HIGHT OF TRIANGLE ABC = 4CM

AND HIGHT OF TRIANGLE DBC = 6 CM

NOW THE AREA OF TRIANGLE

= \frac{1}{2} (base \: \times height)=21(base×height)

NOW THE AREA OF TRIANGLE ABC ( BASE = BC AND HEIGHT = 4CM )

=

\frac{1}{2} (bc \: \times 4)21(bc×4)

= \: {2bc}^{2}=2bc2

so \: now \: \: area \: of \: triangle \: \: dbc \: ( \: base \: = \: bc \: and \: heigt \: = 6cm)sonowareaoftriangledbc(base=bcandheigt=6cm)

AREA =

\frac{1}{2} ( \: bc \times \: 6 \: cm) \: = \: {3bc}^{2}21(bc×6cm)=3bc2

NOW AREA OF ABC UPON AREA OF DBC

WE HAVE

\frac{ {2bc}^{2} }{ {3bc}^{2} } = \frac{2}{3} \: \: hence \: the \: ratio \: of \: the \: area \: of \: triangle \: is3bc22bc2=32hencetheratiooftheareaoftriangleis

2 : 3