Question

the height of two poles ​

Answer 1

$</p><p>\huge\underline\mathfrak\red{Explanation:}$

Heights of the poles = 28m , 36m

difference b/w there heights = (36-28)m = 8m

now, applying Pythagoras theorem

since, b/w there height difference and base distance, a right angled ∆ will form

therefore

$height = \sqrt{ {8}^{2} + {15}^{2} } \: m$

$height \: = \: 17m$

HOPE IT WILL HELP U..

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Answer 2

Answer:

17

Step-by-step explanation:

the explanation you can get in that emails in the image where is to pause consider them as a b and x y ok now a b is placed in front of the X Y so is highest is 28 m and xy height is 36 m now subtracting the height of Ab from xy we get 8 metres consider the point Z which is at the same height of B therefore y z equals to 8 metres now given distance between two poles is 15 m so the length of BZ it will be 15 metres now we are containing a right angle triangle that is b z y and we know the dimensions of B Z and z y which are the height and base so subsequently we can get the length of B and Y by applying Pythagoras theorem