The height of two poles are x and y meter respectively. If the poles are a meter apart then the point of intersection of the lines joining the top of each pole from opposite foot of the pole is given by.
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Let AB and CD be two poles of heights a metres and b metres respectively such that the poles are p metres apart i.e.AC=p metres. Suppose the lines AD and BC meet at O such that OL=h metres.
Let CL=x and LA=y. Then, x+y=p.
In △ABC and △LOC, we have
∠CAB=∠CLO [Each equal to 90∘]
∠C=∠C [Common]
∴ △CAB∼△CLO [By AA-criterion of similarity]
⇒ CLCA=LOAB
⇒ xp=ha
⇒ x=aph
In △ALO and △ACD, we have
∠ALO=∠ACD [Each equal to 90∘]
∠A=∠A [Common]
∴ △ALO∼△ACD [By AA-criterion of similarity]
⇒ ACAL=DCOL
⇒ py=b
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