Question

The height y and distance x along the horizontal plane of a projectile on a certain planet are given y=8t−5t2 (mtr) and x=6t (mtr). the acceleration due to gravity is:

Answer 1

displacement is equal to UT plus half g t square I think the body is moving in opposite direction there by gravity is taken as a negative 5 square is equal to half GT square by cancelling of Tsquare we get G value as 10 M per second square