Question

The height y and horizontal distance x covered by a projectile in a time t seconds are given by the equations y=8t−5t2 and x=6t. If x and y are measured in meters, the velocity of projection is:-

Answer 1

Answer:

Here's ur answer

Explanation:

x=6t

on differentiating with respect to t

v

x

=6

y=8t−5t

2

v

y

=8−5t

at t=0 v

y

=8

v

2

=6

2

+8

2

=10

2

v=10m/s