Question

The height y and horizontal distance x covered by a projectile in a time t seconds are given by the equations y=8t−5t^2 and x=6t where t is in seconds the angle at which the projectile was projected is​

Answer 1

Answer : 10 ms−1

Explanation:

x=6t

on differentiating with respect to t

vx=6

y=8t−5t 2

v y=8−5t

at t=0 vy =8

v 2=62+82=102

v=10m/s