Question

The height y and the distance x along the horizontal plane of projectile projected at a planet (with no surrounding atmosphere) are given by x = 8 t and y = 6 t – 10 t2 where x and y are in metres and t in seconds. The angle of projection with the horizontal at which projectile is projected is​

Answer 1

Explanation:

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VERIFIED✔

The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m, where t is in seconds.

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Answer 2

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The height y nad the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t - 5t^2) m and x = 6t m, where t is in seconds.

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