Question

The heights of 50 students, measured to the nearest centimetres, have been found to be as follows: 154 161 150 154 165 168 161 162 150 151 162 164 171 165 158 154 156 172 160 170 153 159 161 170 162 165 166 168 165 164 154 152 153 156 158 162 160 161 173 166 161 159 162 167 168 159 158 153 154 159 (1) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160-165, 165 - 170, etc. (i) What can you conclude about their heights from the table? the air in​

Answer 1

Answer:

16x²

Step-by-step explanation:

Let the number be x

20% of x=10020×x=5x

The increased number is =x+5x=56x

Let the percentage decrease be 100-y

100y×56x=x

y=6500=83.33%

So 100−y=100−83.33=16.67

Percentage decrease should be 16.67%

Answer 2

Answer:

Height (in cm) Frequency

150−155 12

155−160. 9

160−165 14

165−170. 10

170−175. 5

Total 50

(i) The above table is the grouped frequency distribution.

(ii) Students with 160−165cm heights are maximum i.e. 14 students.

hope it help..