Question

the heights of triangle ABC and triangle DBC are 4 cm and 6cm respectively. find triangle A( ABC)/A( DBC)
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Answer 1

Answer:

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Question:

The heights of triangle ABC and triangle DBC are 4 cm and 6cm respectively. find triangle

$\large\sf{\frac{A( ABC)}{A( DBC)}} </p><p>A(DBC)</p><p>A(ABC)$

Given data:

the heights of triangle ABC and triangle DBC are 4 cm and 6cm respectively

To find:

The triangle \large\sf{\frac{A( ABC)}{A( DBC)}}

A(DBC)

A(ABC)

Solution:

∆ABC & ∆ DBC have a common base BC.

Now their Area depends on their height —— (similarity of triangles)

$\begin{gathered} : \implies\sf{\frac{A( ∆ABC)}{A( ∆DBC)}} = \frac{h_1}{h_2} = \sf{ \cancel{ \frac{4}{6} }} = \sf{ \frac{2}{3} } \\ \\ \therefore \: \: \boxed{ \sf{ \red{ \underline{\frac{A( ∆ABC)}{A( ∆DBC)} = \frac{2}{3} }}}} \\ \\ \\ \boxed{ \mathfrak{ \pink{ \underline{A(∆ABC):A(∆DBC) = 2:3}}}}\end{gathered}$

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Brainliest pls♥️