The hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin plating it on the insidr at the rate of Rs.4 per 100 m.sq
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inner diameter = 10.5
inner radius (r)= 10.5/2=5.25
inner surface area = 2pier^2
= 2×22/7×(5.25)^2= 173.25 cm^2
cost of tin plating at the rate of rs 4 per 100 cm^2
= 4/100 × 173.25=6.93 rs.....
hope his will help you
please give brainlist
inner radius (r)= 10.5/2=5.25
inner surface area = 2pier^2
= 2×22/7×(5.25)^2= 173.25 cm^2
cost of tin plating at the rate of rs 4 per 100 cm^2
= 4/100 × 173.25=6.93 rs.....
hope his will help you
please give brainlist
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