Question

The hero of a stunt film fires 50 g bullets from a machine gun, each at a speed of 1.0 km/s. If he fires 20 bullets in 4 seconds, what average force does he exert against the machine gun during this period ?​

Answer 1

Answer:

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Answer 2

Answer:

Given:

.Hero of a stunt film fires 50g

bullets from a machine gun and

each at a speed of 1.0 km/s.

To find:

Average force exerted against the

machine gun during this period if he fires

20 bullets in 4 seconds.

Solution:

We know that,

p = mv

where, p is momentum

m is mass

and v is velocity.

So, by substituting the known values here,

Momentum of each bullet = 50 g × 1.0 km/s

Now, the rate of change of momentum of the gun

$\begin{gathered} = \frac{50 \: kgm/s \: \times 20 }{4 \: s} \\ \\ = 250 \: N\end{gathered}$

Hence, the average force that the hero exert against the Machine during this period is 250 N.