The hieght of a cone is 30cm. a small cone is cut off at the top by a plane parallel to the base. if its volume be 1/27 of the volume of the given cone,at what height above the base is the section cut
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Consider ∆ADC & ∆ AGF
They are similar ∆s
=> AD/DC = AG/GF
Let the radius of base & height of smaller cone be r & h respectively.
=> AG = h & GF = r
=> h/r = 30/3 = 10
=> h = 10r
Volume of small Cone = 1/3 πr^2h
= 1/3π r^2 x 10r
= 1/3 π x 10 x r^3
Now it is given that :
1/3 π x 10 x r^3 = 1/27 x 1/3π x 9 x 30
=> r^3 = 1 => r = 1
=> h = 10r = 10
So, the cone must be cut 30 - 10 = 20 cms from the base.
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