The high voltage in a TV receiver is 17 kV . The minimum allowable current 150 uA what is the least permissible of load resistance?
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FINAL ANSWER:
11.3333 ohm
GIVEN:
TV receiver is 17 kV
minimum allowable current 150 uA
TO FIND:
what is the least permissible of load resistance
FORMULA USED:
V=I×R
HERE
V = VOLT (V)
I = CURRENT (A)
R = RESTANCE (Ω)
SOLUTION:
V=I×R
17000=150×R
R=17000/150
R=11.3333 Ω
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