the highest energy in Balmer series in emission spectra of hydrogen is represented by(RH=109737 cm^-1)
Answer =27434.25 cm^-1
Answers
Answer:
The highest energy in Balmer series, in the emission spectra of hydrogen is represented by:
\left({R}_{H}=109737 {cm}^{-1}\right)(R
H
=109737cm
−1
)
Asked on November 22, 2019 byavatar
Manas Phalebhay
ANSWER
\bar{v}=\dfrac{1}{\lambda}=R_H{Z}^{2}\left[\dfrac{1}{{n}_{1}^{2}} - \dfrac{1}{{n}_{2}^{2}}\right]
v
ˉ
=
λ
1
=R
H
Z
2
[
n
1
2
1
−
n
2
2
1
]
=109737 \times {1}^{2} \left[\dfrac{1}{{2}^{2}} - \dfrac{1}{{\infty}^{2}}\right] = 27434.25 {cm}^{-1}=109737×1
2
[
2
2
1
−
∞
2
1
]=27434.25cm
−1
(series limit will be of highest energy)
VIDEO EXPLANATION
Explanation:
As we know the energy of constant state for hydrogen species like Li
+
2 or He
+
are multiple of integral type of Z
2
times the energy of hydrogen atom in stationary form,
Hence the wave number of first line of ion $$= 3^2 \times 15200 / cm$$
$$= 9 \times 15200 / cm = 136800 / cm$$
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