Question

The highest excited state that unexcited hydrogen atom can reach when they are bombarded with 12.2 eV
electron is

Answer 1

Answer:

Explanation:

E1=−13.6eV ( energy of hydrogen in n=1)

After absorpton of 12.2eV energy  

En = −13.6+12.2= - 1.5 eV

Now En = E1/n1^2

-1.5 eV = -13.6 eV/1.5

n1^2 = 9

∴n=3 .

hope you understood.

Answer 2

Answer:

2

Explanation:

E0= −13.6eV

En = - 1.5 eV    (−13.6+12.2)

En = -13.6/n^2

-1.5 eV = -13.6/n^2

n^2 = 9(approx)

n=3 .

so maximum state it can reach n-1=2