the highest score in an inning is 1/9 of the total runs scored and the second highest score was 1/9 of the rest. if the scores differ by 7,find the total rums scored in that inning
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Total runs scored by the player in 40 innings = 40 × 50
Total runs scored by the player in 38 innings after excluding two innings = 38 × 48
Sum of the scores of the excluded innings = 40 × 50 - 38 × 48 = 2000 - 1824 = 176
Given that the scores of the excluded innings differ by 172. Hence let's take
the highest score as x + 172 and lowest score as x
Now x + 172 + x = 176
=> 2x = 4
=> x =42 = 2
Highest score = x + 172 = 2 + 172 = 174
Total runs scored by the player in 38 innings after excluding two innings = 38 × 48
Sum of the scores of the excluded innings = 40 × 50 - 38 × 48 = 2000 - 1824 = 176
Given that the scores of the excluded innings differ by 172. Hence let's take
the highest score as x + 172 and lowest score as x
Now x + 172 + x = 176
=> 2x = 4
=> x =42 = 2
Highest score = x + 172 = 2 + 172 = 174
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