Question

The highest score in an inning was 3/11 of the total and the next highest was 3/11 of the remainder. If the scores differed by 63, find the total score.

Answer 1

GIVEN ;-


⇒ Highest score in an inning of the total  = 3 / 11

⇒ Next highest score of the remainder    = 3 / 11

⇒  score differs                                     = 63    


TO FIND ;-

⇒ The total score = ?


SOL ;-


         ⇒ We dont know the total score , so let us take this as ''x'' 



Total. highest score of the inning = 3 / 11 × x               { Equation 1 }

Second highest score of the remainder    = 3  / 11  × ( 1 - 3 / 11 ) { Equation 2 }

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Now let us subtract Equation 1 from Equation 2, we get as -


                           ⇒   3 / 11   -  3 / 11 ( 1 - 3 /11 )


                            ⇒  3 / 11 ( 1 - 8 /11 ) x         = 9


                          ⇒    3 / 11 ( 3 / 11 )  x            = 9


                                   x = 9 × 11 × 11 / 3 ×3


                         ⇒ x =  99 × 11 / 3 × 3


                         ⇒ x = 121


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Therefore the total score is 121.

Answer 2

Solution :
  Let the total score = x
therefore , according to the question
     Highest score in an inning = 3/11 *x
hence , remainder score = total score - highest score
                                   = x - 3x/11 = (11x - 3x)/11 = 8x/11
   Next Highest score = 3/11*8x/11
                                 = (3x/11)*(8/11)

Highest Score - Next highest Score = 63
3x/11 - 3x/11*8/11 = 63
3x/11(1 - 8/11) = 63
3x/11 (11 - 8 )/11 = 63
3x/11*3/11 = 63
3x*3 /11*11 = 63
9x/121 = 63
9x = 63*121
x=63*121/9
x=7*121
x=847

Hence total score = 847

Thank You ^_^