Question

the hight of a parallelogram is one third of its base .if the area of parallelogram 192cm2 find its height and base

Answer 1

let the base be x cm and height be 1/3 x..... area of parallelogram = base * height
192 = x *1/3x
x square = 192 *3
x square = 576
x = 24 cm
height = 1/3 *24 = 8
base = 24 cm :)

Answer 2

Answer:

height = 8 cm

base = 24 cm  

Step-by-step explanation:

According to the question

let the base of a parallelogram, b = $x$

and the height of a parallelogram, h = $\frac{x}{3}$

Area of a parallelogram, A = $192\ cm^{2}$

We know that

Area of a parallelogram, A = b x h

$192 = x\times \frac{x}{3}$

$192\times3 = x^{2}$

$576 = x^{2}$

$\sqrt{576} = x$

∴ $x = 24$

and $\frac{x}{3} = \frac{24}{3} = 8$

height = 8 cm

base = 24 cm   (Answer)