the hight of a right circular cylinder with lateral surface area 792 cm is 21 cm. find the diameter of its base
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given h=21 cm
l.s.a = 792 cm sq.
2*pi*r*h = 792
2*22/7*r*21 = 792
r = 792*1/2*7/22*1/21
= 792*7
2*22*21
r= 6 cm
diameter = 2r = 12 cm
l.s.a = 792 cm sq.
2*pi*r*h = 792
2*22/7*r*21 = 792
r = 792*1/2*7/22*1/21
= 792*7
2*22*21
r= 6 cm
diameter = 2r = 12 cm
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