Question

The hinge of a door is at a distance of 25cm from the point of application of force. How much force must be applied so that it produces the moment of force of 4nm?

Answer must be in latex. ​

Answer 1

⇝Given :-

• Distance =25cm
• Momentum = 5nm

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

⇝To Find :-

• Force = ?

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

⇝Formula Used :-

${\red{\bigstar \: \: {\orange{\underbrace{\underline{\green{\bf{Force = \frac{momentum}{distance} }}}}}}}}$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

⇝Solution :-

❒ Here :

Force = ?

Momentum = 4nm

Distance = 25cm

❒ Solving Starts :

${:{\twoheadrightarrow{\bf \: \: \: \: \: \: \: \: \: \: \: {Force = \frac{momentum}{distance} }}}}$

${:{\twoheadrightarrow{\bf \: \: \: \: \: \: \: \: \: \: \: {Force = \frac{4 \times{\cancel {100}}}{\cancel{25}} }}}}$

${:{\twoheadrightarrow{\bf \: \: \: \: \: \: \: \: \: \: \: {Force = 4 \times 4 }}}}$

${\large{\purple{:{\longmapsto{\underline{\boxed{\bf{Force = 16 N}}}}}}}}$

❒ Therefore :

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\large{\purple{\underline{\red{\underline{\pink{\pmb{\mathfrak{Force = 16 N}}}}}}}}}$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

❒ More Info :

✏3 Laws of motion :

$\begin{gathered}\red{\large \qquad \boxed{\boxed{\begin{array}{cc} \ ➳ \: \: \bf v = u + at \\ \\ \ ➳ \: \: \bf s = ut + \dfrac{1}{2}a {t}^{2} \\ \\ \ ➳ \: \: \bf{v}^{2} - {u}^{2} = 2as\end{array}}}}\end{gathered}$

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

Answer 2

➩GIVEN :-

• Distance = 25 cm
• Momentum = 4 nm

➩TO FIND :-

• Force

➩SOLUTION :-

We know that,

$\sf \red \star \fbox \blue{Force = \frac{Momentum}{Distance}}$

$\sf {{{→Force = \frac{4 \times{\cancel {100}}}{\cancel{25}}}}}$

$\sf {→Force = 4 × 4}$

$\sf \fbox \orange{→Force \: = \: 16N}$

$\therefore$ 16N of force must be applied so that it produces the moment of force of 4nm.

❒KNOW MORE :-

✏3 Laws of motion :-

$\sf →\green{v = u + {at}^{2}}$

$\sf →\red{s = ut + \frac{1}{2} {at}^{2}}$

$\sf →\orange{{v}^{2} - {u}^{2} = 2as}$