Physics, asked by Vedansh79, 7 months ago

The hinge of a door is at a distance of 35 cm from the point of application of force. How much force must be applied so that it produces the moment of force of 5 Nm?

Answers

Answered by NIyati2204
1

Explanation:

torque = Force x Perpendicular distance.

F = T/ r

r = 35/100 m

F = 5 x 100/35 = 100/7 = 14.28 N

Answered by KhataranakhKhiladi2
8

As we know ,

Mumentum = Force × displacement

Force = Mumentum / Distance

Force = (5× 100)/35

= 100/7

= 14.2N

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