Question

The horizontal and vertical components of Earth’s magnetic field at a place are 0.22G and 0.38Grespectively. Calculate the angle of dip and resultant intensity of Earth’s magnetic field.

Answer 1

horizontal component of earth's magnetic field , $B_H=0.22G$

vertical component of earth's magnetic field, $B_V=0.38G$

formula of angle of dip, $\delta=tan^{-1}\frac{B_V}{B_H}$

= $tan^{-1}\frac{0.38}{0.22}$

=$tan^{-1}\frac{19}{11}$

and resistant intensity of earth's magnetic field , $B=\sqrt{B_V^2+B_H^2}$

= $\sqrt{(0.38)^2+(0.22)^2}$

= 0.439G ≈ 0.44G

hence, resistant of intensity of earth's magnetic field is 0.44G