Question

the horizontal and vertical components of projecting velocity of a projectile is 10m/s and 20m/s. the range of the projectile is(g=10 m/s^2)

Answer 1

Answer:

see the attachment

Explanation:

hope the answer will help you

Answer 2

Explanation:

using v=u+at, where u=20, v=0, a=g=10,

we get t = 2

therefore time if flight = 4 s

now range = 4 * horizontal velocity

= 4*10

= 40 m