Question

The horizontal and vertical displacements x and y of projectile at a given time 't' are given by x=6t meters and y=8t-5t×5t meters The range of the projectile in meters is​

Answer 1

Oaks I will answer you someday after

Answer 2

answer:-

10 m/s

expiation:-

givenY=8t-5t^2

       X=6t

       by equations of derivations we get:-  

        Velocity of X=6m/s and velocity of Y =8m/s

       velocity of projectiom is √6^2+8^2 we get 10 m/s      Answer: