Question

the horizontal and vertical distance travelled by a particle in time T are given by x is equal to 6t and Y is equal to 80 - 5 t square. If g is equal to 10 metre per second square then the initial velocity of particle is
A)8 metre per second
B)10 metre per second
C)5 metre per second
D)0 ​

Answer 1

Answer:

solution :- x = 6t

differentiate x with respect to time t

dx/dt = 6 = x - component of initial velocity =Vx

y = 8t - 5t²

differentiate y with respect to time t

dy/dt = 8 - 10t

At t = 0, dy/dt = 8 = y - component of intial velocity = By

Now, |V| = √(Vx² + Vy²) = √(6² + 8²) = 10m/s

so, answer is B

Explanation: