Question

The horizontal and verticle distances travelled by a particle in time t are given by x = 6t and
y = 8t - 5t². If g = 10 /sec², then the initial velocity of the particle is-
(1) 8 m/sec
(2) 10 m/sec
(3) 5 m/sec
(4) Zero​

Answer 1

Answer:

✯Answer:

(2) 10 m/sec

✯Given:

• The horizontal and verticle distances travelled by a particle in time t are given by x = 6t
• and
• y = 8t - 5t². If g = 10 /sec²,

✯To Find:

initial velocity of the particle is

✯solution :

x = 6t

differentiate x with respect to time t

dx/dt = 6 = x - component of initial velocity =Vx

y = 8t - 5t²

differentiate y with respect to time t

dy/dt = 8 - 10t

At t = 0, dy/dt = 8 = y - component of intial velocity = By

Now, |V| = √(Vx² + Vy²) = √(6² + 8²)

✯10m/sec

Answer 2

Answer:

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