the horizontal asymptote of the curve y=3arctan(2x)
Answers
Answered by
1
Given : y=3arctan(2x)
To Find : horizontal asymptote
Solution:
y=3arctan(2x)
=> y = 3 tan⁻¹(2x)
horizontal asymptote y = 3 ( ±π/2)
y = ±3π/2
=> y = ± 4.71 taking π = 3.14
Learn More:
If y = tan-1 x, show that ( 1 + x2) d2y / dx2 + 2x dy/dx = 0
brainly.in/question/3206880
The tangent to the curve y = x2 + 3x will pa ss through the point 0, - 9
brainly.in/question/11223243
Attachments:
Similar questions