Question

The horizontal component of force 10N inclined at 30 degree to the vertical is. ?

Answer 1

Explanation:

that is solution............

Answer 2

The vertical component of force is 5.77 N.

Explanation:

Horizontal component of force is , F = 10 N

Angle, $\theta=30^{\circ}$

The horizontal component of force is given by :

$F_x=F\cos \theta\\\\10=F\cos(30)\\\\F=\dfrac{10}{\cos (30)}\\\\F=11.54\ N$

The vertical component of force is given by :

$F_y=F\sin \theta\\\\F_y=11.54\times \sin(30)\\\\F_y=5.77\ N$

So, the vertical component of force is 5.77 N.

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The horizontal component of force 10 N inclined at 30 degree to the vertical is ?