Question

The horizontal component of the earth's magnetic field at a certain
place is 2.6 x 10^-5T and the angle of dip is 60°. What is the magnetic
field of the earth at this location ?​

Answer 1

Explanation:

B cos 60⁰ = H

B √3/2 = 2.6 x 10^-5

B = (5.2 x 10^-5 )/ √3 T