Physics, asked by bashavenisaiteja, 15 days ago

The horizontal component of the earth's magnetic field at a place is 3x10-4 and the dip is = tan (4/3). A metal rod of length 0.25m placed in the north-south position is moved at a constant speed of 10 cm/s towards the east. The e.m.finduced in the rod will be 1) zero 2) 1 mV 3) 5 mV 4) 10mVटीटा ​

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Answered by pruthvish177
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Answer:

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