Question

The horizontal distance between two poles is 15m. The angles of depression of the top of the first pole as seen from the top of the first pole is 30⁰ If it's flying at a speed of 720km/hr find the constant height at which the jet is flying ​

Answer 1

Answer:

in ΔBED,   tan30  ∘  = 3 1 =  15 x x=5 3 m

Height of first pole =AB=AE+BE=24m+5  

3 m  =(24+5  3 )m

Step-by-step explanation: