The horizontal distance between two towers is 120m. The angle of elevation of
the top and angle of depression of the bottom of the first tower as observed from
the second tower are 30° and 24° respectively. Find the height of the two towers.
Give your answer correct to 2 decimal places.
Answers
Answer:
122.4 and 53.424
Step-by-step explanation:
please check attach image
10th
Maths
Some Applications of Trigonometry
Heights and Distances
The horizontal distance bet...
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Asked on October 15, 2019 by
Sachin Kamakshi
The horizontal distance between two towers is 120m. The angle of elevation of the top and angle of depression of the bottom of the first tower as observed from the second tower is 30
o
and 24
o
respectively.
Find the height of the two towers. Give your answer correct to 4 significant figures.
577650
HARD
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VIDEO EXPLANATION
ANSWER
Let AB and CD are two towers.
BD=120m=EC, ∠ACE=30
o
, ∠CBD=24
o
.
In right angle △CBD,
tan24
o
=
BD
CD
=
120
CD
CD=120×0.4452
=53.42m
In right angle △ACE,
tan30
o
=
EC
AE
=
120
AE
AE=120×0.5773
=69.28m
AB=AE+EB
=AE+CD [EB=CD]
=69.28+53.42
=122.7m
Height of 1
st
tower is 122.7m and 2
nd
tower is 53.42m.