Question

The horizontal distance between two towers is 140 m. The angle of elevation of the top of the tower CD when seen from the top of tower AB is 30°. if the height of the tower AB=60m find the height of the tower CD.
take √3=1.73
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Answer 1

given AB=60m

ABED is rectangle

ED=60m

AE=BD=140m

angleCAE=30°

from ∆CAE

Tan 30°=CE/AE

1/√3=CE/140

=140/√3=CE

CE=140/1.732

CE=80.831

CD=CE+ED

CD=80.83+60

=140.83

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