The horizontal distance between two towers is 70m. The angles of depression of the top of the first tower, when seen from the top of the second tower is 30°. If the height of the second tower is 120m, find the height of the first tower. (Pls the answer is supposed to be 79.6m)
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let height of the first tower be x + 120m
tan 30° = x/70
1/√3 = x/70
x = 70/√3
x = 40.41m
h = x + 120 = 40.41 + 120 = 160.41
Hey, to my knowledge this is the answer.
Maybe your answer has a printing mistake.
Anyway, hope this helps.
tan 30° = x/70
1/√3 = x/70
x = 70/√3
x = 40.41m
h = x + 120 = 40.41 + 120 = 160.41
Hey, to my knowledge this is the answer.
Maybe your answer has a printing mistake.
Anyway, hope this helps.
grakshitaow0i4v:
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