Question

the horizontal distance between two towers is 80m ,the angle of elevation of the top of secound tower fis 60 degree. if the height of the secound tower is 50m.them find the height of the first tower?​

Answer 1

Answer:

As the Angle of Depression is given from the top of Second Tower

Hence, Second Tower is Larger than the First,so we can clearly see that, Height of First Tower must be less than the Height of the Second Tower (=150 m)

We can see that, BCDE is a Rectangle

so, BC=ED=60

BE=CD=h (Let)

Now, in △AED

tan60

o

=

ED

AE

3 = 60AE

⇒AE=60

√3

So, Height of First Tower is h=BE=AB−AE=150−60 √3