The horizontal distance between two towers is150 m. The angle of depression of the top of the first tower as observed from the top of the
second tower which is 120 m in height is 300. Find the height of the first tower. [Give your answer nearest to meter]
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Step-by-step explanation:
Let AB and CD are two towers.
BD=120m=EC, ∠ACE=30
o
, ∠CBD=24
o
.
In right angle △CBD,
tan24
o
=
BD
CD
=
120
CD
CD=120×0.4452
=53.42m
In right angle △ACE,
tan30
o
=
EC
AE
=
120
AE
AE=120×0.5773
=69.28m
AB=AE+EB
=AE+CD [EB=CD]
=69.28+53.42
=122.7m
Height of 1
st
tower is 122.7m and 2
nd
tower is 53.42m.
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