Question

The horizontal force and the force inclined at an angle 60o with the vertical, whose resultant is in the vertical direction of ‘P’ kg, are​

Answer 1

Explanation:

Let {OA}

OA

= P1 i,

\{CB}

CB

= −P1 i,

{OB}

OB

= −P1i + Pj

\frac{\{OB}.{j}}{OB}=cos60^o

OB

OB

.j

=cos60

o

⇒ [(−P1i + Pj) . j] / [√P21 + P2] = [1 / 2]

⇒ 2P = [√P21 + P2]

⇒ P1 = P√3

|{OB}|∣

OB

∣ = [√P21 + P2]

= √[P2 + 3P2]

= 2P