Question

The horizontal range and maximum height attained by a projectile are r and h respectively

Answer 1

Answer:

plzzz give me brainliest ans and plzzzz follow me

Answer 2

Answer:

Explanation:

Normal projectile motion , with no acceleration in horizontal direction.

H =  u² sin² Ф / 2g                u = initial speed, Ф angle of projection

R =  u² sin 2Ф / g

With a constant acceleration due to wind in horizontal direction:

Time of flight remains same and is dependent on vertical component of velocity.

H"  = same as H = u² sin² Ф / 2 g                as there is no modification in y direction

R"  = [u² sin 2Ф / g ] +  1/2 (g/4)  (2 u sin Ф÷g)²  , as    acc = g÷4     t= 2 u sinФ÷g

     = u² sin 2Ф / g + 1/2 u² sin² Ф / g

     = R + H

Hope it helps you...