Question

the horizontal range and maximum height of a projectile are equal the angel of projection of the projectile is ​

Answer 1

The range of a projective is given by,

$R = \frac{ {u}^{2}sin2 \theta }{g}$

Maximum Height of a projectile is given by,

$h= \frac{ {u}^{2}sin ^{2} \: \theta }{2g}$

Given,

Maximum Height of the projectile is equal to the Range of the projectile.

So,

R = H

which implies,

$\implies \frac{ {u}^{2}sin 2 \theta }{g} = \frac{ {u}^{2}sin ^{2} \theta }{2g} \\ \\ \implies \: sin2 \theta = \frac{ sin ^{2} \theta }{2}\\ \\ \implies \:2 \times 2 \: sin \theta \: cos \theta = sin ^{2} \theta \\ \\ \implies \: 4 \cos\theta = \sin( \theta) \\ \\ \implies \: tan\theta = 4\\ \\ \implies \theta = {tan}^{ - 1} ( 4 ) = 76$

Therefore, Angle of projection is 76 degrees approximately.

Answer 2

Answer:

,

Explanation:

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