Question

The horizontal range and the maximum height of a projectile are equal, Then corresponding angle of projection of the projectile is​

Answer 1

Correct option is

C

θ=tan

−1

4 or θ=70

R=

g

u

2

sin2θ

H=

2g

u

2

sin

2

θ

g

u

2

sin2θ

=

2g

u

2

sin

2

θ

2sinθcosθ=

2

sin

2

θ

ucosθ=sinθ

tanθ=4

θ=tan

−1

4